Optimal. Leaf size=443 \[ -\frac{e \left (2 a B d e \left (c d^2-11 a e^2\right )-3 A \left (-5 a^2 e^4+4 a c d^2 e^2+c^2 d^4\right )\right )}{8 a^2 (d+e x) \left (a e^2+c d^2\right )^3}-\frac{\sqrt{c} \tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right ) \left (2 a B d e \left (-15 a^2 e^4+10 a c d^2 e^2+c^2 d^4\right )-3 A \left (15 a^2 c d^2 e^4-5 a^3 e^6+5 a c^2 d^4 e^2+c^3 d^6\right )\right )}{8 a^{5/2} \left (a e^2+c d^2\right )^4}-\frac{x \left (2 a B e \left (c d^2-2 a e^2\right )-3 A c d \left (3 a e^2+c d^2\right )\right )+a e \left (-5 a A e^2+6 a B d e+A c d^2\right )}{8 a^2 \left (a+c x^2\right ) (d+e x) \left (a e^2+c d^2\right )^2}-\frac{a (B d-A e)-x (a B e+A c d)}{4 a \left (a+c x^2\right )^2 (d+e x) \left (a e^2+c d^2\right )}+\frac{e^4 \log \left (a+c x^2\right ) \left (-a B e^2-6 A c d e+5 B c d^2\right )}{2 \left (a e^2+c d^2\right )^4}-\frac{e^4 \log (d+e x) \left (-a B e^2-6 A c d e+5 B c d^2\right )}{\left (a e^2+c d^2\right )^4} \]
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Rubi [A] time = 0.724492, antiderivative size = 443, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.227, Rules used = {823, 801, 635, 205, 260} \[ -\frac{e \left (2 a B d e \left (c d^2-11 a e^2\right )-3 A \left (-5 a^2 e^4+4 a c d^2 e^2+c^2 d^4\right )\right )}{8 a^2 (d+e x) \left (a e^2+c d^2\right )^3}-\frac{\sqrt{c} \tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right ) \left (2 a B d e \left (-15 a^2 e^4+10 a c d^2 e^2+c^2 d^4\right )-3 A \left (15 a^2 c d^2 e^4-5 a^3 e^6+5 a c^2 d^4 e^2+c^3 d^6\right )\right )}{8 a^{5/2} \left (a e^2+c d^2\right )^4}-\frac{x \left (2 a B e \left (c d^2-2 a e^2\right )-3 A c d \left (3 a e^2+c d^2\right )\right )+a e \left (-5 a A e^2+6 a B d e+A c d^2\right )}{8 a^2 \left (a+c x^2\right ) (d+e x) \left (a e^2+c d^2\right )^2}-\frac{a (B d-A e)-x (a B e+A c d)}{4 a \left (a+c x^2\right )^2 (d+e x) \left (a e^2+c d^2\right )}+\frac{e^4 \log \left (a+c x^2\right ) \left (-a B e^2-6 A c d e+5 B c d^2\right )}{2 \left (a e^2+c d^2\right )^4}-\frac{e^4 \log (d+e x) \left (-a B e^2-6 A c d e+5 B c d^2\right )}{\left (a e^2+c d^2\right )^4} \]
Antiderivative was successfully verified.
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Rule 823
Rule 801
Rule 635
Rule 205
Rule 260
Rubi steps
\begin{align*} \int \frac{A+B x}{(d+e x)^2 \left (a+c x^2\right )^3} \, dx &=-\frac{a (B d-A e)-(A c d+a B e) x}{4 a \left (c d^2+a e^2\right ) (d+e x) \left (a+c x^2\right )^2}-\frac{\int \frac{-c \left (3 A c d^2-2 a B d e+5 a A e^2\right )-4 c e (A c d+a B e) x}{(d+e x)^2 \left (a+c x^2\right )^2} \, dx}{4 a c \left (c d^2+a e^2\right )}\\ &=-\frac{a (B d-A e)-(A c d+a B e) x}{4 a \left (c d^2+a e^2\right ) (d+e x) \left (a+c x^2\right )^2}-\frac{a e \left (A c d^2+6 a B d e-5 a A e^2\right )+\left (2 a B e \left (c d^2-2 a e^2\right )-3 A c d \left (c d^2+3 a e^2\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^2 (d+e x) \left (a+c x^2\right )}+\frac{\int \frac{-c^2 \left (2 a B d e \left (c d^2+7 a e^2\right )-3 A \left (c^2 d^4+2 a c d^2 e^2+5 a^2 e^4\right )\right )-2 c^2 e \left (2 a B e \left (c d^2-2 a e^2\right )-3 A c d \left (c d^2+3 a e^2\right )\right ) x}{(d+e x)^2 \left (a+c x^2\right )} \, dx}{8 a^2 c^2 \left (c d^2+a e^2\right )^2}\\ &=-\frac{a (B d-A e)-(A c d+a B e) x}{4 a \left (c d^2+a e^2\right ) (d+e x) \left (a+c x^2\right )^2}-\frac{a e \left (A c d^2+6 a B d e-5 a A e^2\right )+\left (2 a B e \left (c d^2-2 a e^2\right )-3 A c d \left (c d^2+3 a e^2\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^2 (d+e x) \left (a+c x^2\right )}+\frac{\int \left (\frac{c^2 e^2 \left (2 a B d e \left (c d^2-11 a e^2\right )-3 A \left (c^2 d^4+4 a c d^2 e^2-5 a^2 e^4\right )\right )}{\left (c d^2+a e^2\right ) (d+e x)^2}+\frac{8 a^2 c^2 e^5 \left (-5 B c d^2+6 A c d e+a B e^2\right )}{\left (c d^2+a e^2\right )^2 (d+e x)}+\frac{c^3 \left (-2 a B d e \left (c^2 d^4+10 a c d^2 e^2-15 a^2 e^4\right )+3 A \left (c^3 d^6+5 a c^2 d^4 e^2+15 a^2 c d^2 e^4-5 a^3 e^6\right )+8 a^2 e^4 \left (5 B c d^2-6 A c d e-a B e^2\right ) x\right )}{\left (c d^2+a e^2\right )^2 \left (a+c x^2\right )}\right ) \, dx}{8 a^2 c^2 \left (c d^2+a e^2\right )^2}\\ &=-\frac{e \left (2 a B d e \left (c d^2-11 a e^2\right )-3 A \left (c^2 d^4+4 a c d^2 e^2-5 a^2 e^4\right )\right )}{8 a^2 \left (c d^2+a e^2\right )^3 (d+e x)}-\frac{a (B d-A e)-(A c d+a B e) x}{4 a \left (c d^2+a e^2\right ) (d+e x) \left (a+c x^2\right )^2}-\frac{a e \left (A c d^2+6 a B d e-5 a A e^2\right )+\left (2 a B e \left (c d^2-2 a e^2\right )-3 A c d \left (c d^2+3 a e^2\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^2 (d+e x) \left (a+c x^2\right )}-\frac{e^4 \left (5 B c d^2-6 A c d e-a B e^2\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^4}+\frac{c \int \frac{-2 a B d e \left (c^2 d^4+10 a c d^2 e^2-15 a^2 e^4\right )+3 A \left (c^3 d^6+5 a c^2 d^4 e^2+15 a^2 c d^2 e^4-5 a^3 e^6\right )+8 a^2 e^4 \left (5 B c d^2-6 A c d e-a B e^2\right ) x}{a+c x^2} \, dx}{8 a^2 \left (c d^2+a e^2\right )^4}\\ &=-\frac{e \left (2 a B d e \left (c d^2-11 a e^2\right )-3 A \left (c^2 d^4+4 a c d^2 e^2-5 a^2 e^4\right )\right )}{8 a^2 \left (c d^2+a e^2\right )^3 (d+e x)}-\frac{a (B d-A e)-(A c d+a B e) x}{4 a \left (c d^2+a e^2\right ) (d+e x) \left (a+c x^2\right )^2}-\frac{a e \left (A c d^2+6 a B d e-5 a A e^2\right )+\left (2 a B e \left (c d^2-2 a e^2\right )-3 A c d \left (c d^2+3 a e^2\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^2 (d+e x) \left (a+c x^2\right )}-\frac{e^4 \left (5 B c d^2-6 A c d e-a B e^2\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^4}+\frac{\left (c e^4 \left (5 B c d^2-6 A c d e-a B e^2\right )\right ) \int \frac{x}{a+c x^2} \, dx}{\left (c d^2+a e^2\right )^4}-\frac{\left (c \left (2 a B d e \left (c^2 d^4+10 a c d^2 e^2-15 a^2 e^4\right )-3 A \left (c^3 d^6+5 a c^2 d^4 e^2+15 a^2 c d^2 e^4-5 a^3 e^6\right )\right )\right ) \int \frac{1}{a+c x^2} \, dx}{8 a^2 \left (c d^2+a e^2\right )^4}\\ &=-\frac{e \left (2 a B d e \left (c d^2-11 a e^2\right )-3 A \left (c^2 d^4+4 a c d^2 e^2-5 a^2 e^4\right )\right )}{8 a^2 \left (c d^2+a e^2\right )^3 (d+e x)}-\frac{a (B d-A e)-(A c d+a B e) x}{4 a \left (c d^2+a e^2\right ) (d+e x) \left (a+c x^2\right )^2}-\frac{a e \left (A c d^2+6 a B d e-5 a A e^2\right )+\left (2 a B e \left (c d^2-2 a e^2\right )-3 A c d \left (c d^2+3 a e^2\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^2 (d+e x) \left (a+c x^2\right )}-\frac{\sqrt{c} \left (2 a B d e \left (c^2 d^4+10 a c d^2 e^2-15 a^2 e^4\right )-3 A \left (c^3 d^6+5 a c^2 d^4 e^2+15 a^2 c d^2 e^4-5 a^3 e^6\right )\right ) \tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right )}{8 a^{5/2} \left (c d^2+a e^2\right )^4}-\frac{e^4 \left (5 B c d^2-6 A c d e-a B e^2\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^4}+\frac{e^4 \left (5 B c d^2-6 A c d e-a B e^2\right ) \log \left (a+c x^2\right )}{2 \left (c d^2+a e^2\right )^4}\\ \end{align*}
Mathematica [A] time = 0.5434, size = 378, normalized size = 0.85 \[ \frac{\frac{\left (a e^2+c d^2\right ) \left (a^2 c e^2 (A e (16 d-7 e x)-2 B d (6 d-7 e x))+4 a^3 B e^4-2 a c^2 d^2 e x (B d-6 A e)+3 A c^3 d^4 x\right )}{a^2 \left (a+c x^2\right )}+\frac{2 \left (a e^2+c d^2\right )^2 \left (a^2 B e^2-a c (A e (e x-2 d)+B d (d-2 e x))+A c^2 d^2 x\right )}{a \left (a+c x^2\right )^2}+\frac{\sqrt{c} \tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right ) \left (3 A \left (15 a^2 c d^2 e^4-5 a^3 e^6+5 a c^2 d^4 e^2+c^3 d^6\right )+2 a B d e \left (15 a^2 e^4-10 a c d^2 e^2-c^2 d^4\right )\right )}{a^{5/2}}-4 e^4 \log \left (a+c x^2\right ) \left (a B e^2+6 A c d e-5 B c d^2\right )-\frac{8 e^4 \left (a e^2+c d^2\right ) (A e-B d)}{d+e x}+8 e^4 \log (d+e x) \left (a B e^2+6 A c d e-5 B c d^2\right )}{8 \left (a e^2+c d^2\right )^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.025, size = 1410, normalized size = 3.2 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.27589, size = 1129, normalized size = 2.55 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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